Bài tập 7 trang 95 SGK Hình học 12

Giải bài 7 tr 95 sách GK Toán Hình lớp 12

Cho mặt phẳng \((\alpha )\) đi qua điểm M(0;0;-1) và song song với giá của hai vecto \(\vec{a}=(1;-2;3)\) và \(\vec{b}=(3;0;5)\).

Phương trình của mặt phẳng \((\alpha )\) là:

(A) 5x - 2y - 3z - 21 = 0

(B) -5x + 2y + 3z + 3 = 0

(C) 10x - 4y - 6z + 21 = 0

(D) 5x - 2y - 3z + 21 = 0

Gợi ý trả lời bài 7

Vecto pháp tuyến của mp \((\alpha )\) là \(\vec{n}=\left [ \vec{a};\vec{b} \right ]=(-10;4;6)\)

Phương trình mp\((\alpha )\):

\(-10(x-0)+4(y-0)+6(z+1)=0\Leftrightarrow -5x+2y+3z+3=0\)

⇒ Chọn đáp án B.

-- Mod Toán 12 HỌC247

Nếu bạn thấy gợi ý trả lời Bài tập 7 trang 95 SGK Hình học 12 HAY thì click chia sẻ 
  • Nguyễn Quang Thanh Tú
    Đề kiểm tra - Đề 3 (Sách bài tập trang 135)

    Trong không gian Oxyz, cho 4 điểm \(A\left(2;4;-1\right),B\left(1;4;-1\right),C\left(1;4;3\right),D\left(2;2;-1\right)\)

    a) Chứng minh rằng các đường thẳng AB, AC, AD vuông góc với nhau từng đôi một

    b) Viết phương trình tham số của đường vuông góc chung \(\Delta\) của hai đường thẳng AB và CD

    c) Viết phương trình mặt cầu (S) đi qua bốn điểm A, B, C, D

    d) Viết phương trình mặt phẳng \(\left(\alpha\right)\) tiếp xúc với mặt cầu (S) và song song với mặt phẳng (ABD)

    Theo dõi (0) 1 Trả lời
  • trang lan
    Bài 3.57 (Sách bài tập trang 132)

    Lập phương trình tham số của đường thẳng d đi qua điểm \(M_0\left(x_0;y_0;z_0\right)\) và vuông góc với mặt phẳng \(\left(P\right):Ax+By+Cz+D=0\) ?

    Theo dõi (0) 1 Trả lời
  • Xuan Xuan
    Bài III.8* - Bài tập bổ sung (Sách bài tập - tập 2 - trang 41)

    Có thể tìm được hai chữ số a và b sao cho phân số \(\dfrac{a}{b}\) bằng số thập phân a,b hay không ?

    Theo dõi (0) 1 Trả lời
  • thu hảo
    Bài III.7* - Bài tập bổ sung (Sách bài tập - tập 2 - trang 41)

    Tìm số tự nhiên có hai chữ số sao cho tỉ số đó với tổng các chữ số của nó là lớn nhất ?

    Theo dõi (0) 1 Trả lời
  • thuy tien
    Bài III.6* - Bài tập bổ sung (Sách bài tập - tập 2 - trang 41)

    Có bao nhiêu cách viết phân số \(\dfrac{1}{5}\) dưới dạng tổng của hai phân số \(\dfrac{1}{a}+\dfrac{1}{b}\) với \(0< a< b\) ?

    Theo dõi (0) 1 Trả lời
  • Thụy Mây
    Bài III.5* - Bài tập bổ sung (Sách bài tập - tập 2 - trang 41)

    Chứng minh rằng :

                    \(S=\dfrac{1}{2}+\dfrac{1}{2^2}+\dfrac{1}{2^3}+...+\dfrac{1}{2^{20}}< 1\)

    Theo dõi (0) 1 Trả lời
  • Anh Trần
    Bài III.4 - Bài tập bổ sung (Sách bài tập - tập 2 - trang 41)

    Tính giá trị biểu thức :

            \(P=\dfrac{2.3.4-2.3.4.9+2.3.4.11+2.3.4.13}{5.6.7-5.6.7.9+5.6.7.11-5.6.7.13}\)

    Theo dõi (0) 1 Trả lời
  • Mai Hoa
    Bài III.1 - Bài tập bổ sung (Sách bài tập - tập 2 - trang 41)

    Phân số \(\dfrac{a}{b}\) sau khi rút gọn được phân số \(\dfrac{-8}{11}\). Biết \(b-a=190\), tìm phân số \(\dfrac{a}{b}\) ?

    Theo dõi (0) 1 Trả lời
  • Lê Thánh Tông
    Bài 155* (Sách bài tập - tập 2 - trang 40)

    Chứng minh rằng :               

                   \(S=\dfrac{1}{5}+\dfrac{1}{13}+\dfrac{1}{14}+\dfrac{1}{15}+\dfrac{1}{61}+\dfrac{1}{62}+\dfrac{1}{63}< \dfrac{1}{2}\)

    Theo dõi (0) 1 Trả lời
  • Ngoc Nga
    Bài 153 (Sách bài tập - tập 2 - trang 40)

    Tìm \(x\), biết :

                  \(\left(\dfrac{1}{12}+3\dfrac{1}{6}-30,75\right)x-8=\left(\dfrac{3}{5}+0,415+\dfrac{1}{200}\right):0,01\)

    Theo dõi (0) 1 Trả lời
  • Nguyễn Hồng Tiến
    Bài 152 (Sách bài tập - tập 2 - trang 40)

    Tính :

                        \(1\dfrac{13}{15}.0,75-\left(\dfrac{104}{195}+25\%\right).\dfrac{24}{47}-3\dfrac{12}{13}:3\)

    Theo dõi (0) 1 Trả lời
  • Tuấn Huy
    Bài 151 (Sách bài tập - tập 2 - trang 40)

    Tìm số nguyên \(x\), biết rằng :

                    \(4\dfrac{1}{3}.\left(\dfrac{1}{6}-\dfrac{1}{2}\right)\le x\le\dfrac{2}{3}.\left(\dfrac{1}{3}-\dfrac{1}{2}-\dfrac{3}{4}\right)\)

    Theo dõi (0) 1 Trả lời
  • Nguyễn Hoài Thương

    a. 2https:https://hoc247.net/image/faq/data2/216985_.https://hoc247.net/image/faq/data2/216985_.hoc247.nethttps://hoc247.net/image/faq/data2/216985_.imagehttps://hoc247.net/image/faq/data2/216985_.faqhttps://hoc247.net/image/faq/data2/216985_.data2https://hoc247.net/image/faq/data2/216985_.563596_.3x-1https:https://hoc247.net/image/faq/data2/216985_.https://hoc247.net/image/faq/data2/216985_.hoc247.nethttps://hoc247.net/image/faq/data2/216985_.imagehttps://hoc247.net/image/faq/data2/216985_.faqhttps://hoc247.net/image/faq/data2/216985_.data2https://hoc247.net/image/faq/data2/216985_.563596_.2=1https:https://hoc247.net/image/faq/data2/216985_.https://hoc247.net/image/faq/data2/216985_.hoc247.nethttps://hoc247.net/image/faq/data2/216985_.imagehttps://hoc247.net/image/faq/data2/216985_.faqhttps://hoc247.net/image/faq/data2/216985_.data2https://hoc247.net/image/faq/data2/216985_.563596_.10

    b. 39https:https://hoc247.net/image/faq/data2/216985_.https://hoc247.net/image/faq/data2/216985_.hoc247.nethttps://hoc247.net/image/faq/data2/216985_.imagehttps://hoc247.net/image/faq/data2/216985_.faqhttps://hoc247.net/image/faq/data2/216985_.data2https://hoc247.net/image/faq/data2/216985_.563596_.7:x=13

    c. (14https:https://hoc247.net/image/faq/data2/216985_.https://hoc247.net/image/faq/data2/216985_.hoc247.nethttps://hoc247.net/image/faq/data2/216985_.imagehttps://hoc247.net/image/faq/data2/216985_.faqhttps://hoc247.net/image/faq/data2/216985_.data2https://hoc247.net/image/faq/data2/216985_.563596_.5x-50):2https:https://hoc247.net/image/faq/data2/216985_.https://hoc247.net/image/faq/data2/216985_.hoc247.nethttps://hoc247.net/image/faq/data2/216985_.imagehttps://hoc247.net/image/faq/data2/216985_.faqhttps://hoc247.net/image/faq/data2/216985_.data2https://hoc247.net/image/faq/data2/216985_.563596_.3=51

    d. (x+1https:https://hoc247.net/image/faq/data2/216985_.https://hoc247.net/image/faq/data2/216985_.hoc247.nethttps://hoc247.net/image/faq/data2/216985_.imagehttps://hoc247.net/image/faq/data2/216985_.faqhttps://hoc247.net/image/faq/data2/216985_.data2https://hoc247.net/image/faq/data2/216985_.563596_.2)(2https:https://hoc247.net/image/faq/data2/216985_.https://hoc247.net/image/faq/data2/216985_.hoc247.nethttps://hoc247.net/image/faq/data2/216985_.imagehttps://hoc247.net/image/faq/data2/216985_.faqhttps://hoc247.net/image/faq/data2/216985_.data2https://hoc247.net/image/faq/data2/216985_.563596_.3-2x)=0

    e. 2https:https://hoc247.net/image/faq/data2/216985_.https://hoc247.net/image/faq/data2/216985_.hoc247.nethttps://hoc247.net/image/faq/data2/216985_.imagehttps://hoc247.net/image/faq/data2/216985_.faqhttps://hoc247.net/image/faq/data2/216985_.data2https://hoc247.net/image/faq/data2/216985_.563596_.3x-1https:https://hoc247.net/image/faq/data2/216985_.https://hoc247.net/image/faq/data2/216985_.hoc247.nethttps://hoc247.net/image/faq/data2/216985_.imagehttps://hoc247.net/image/faq/data2/216985_.faqhttps://hoc247.net/image/faq/data2/216985_.data2https://hoc247.net/image/faq/data2/216985_.563596_.2x=5https:https://hoc247.net/image/faq/data2/216985_.https://hoc247.net/image/faq/data2/216985_.hoc247.nethttps://hoc247.net/image/faq/data2/216985_.imagehttps://hoc247.net/image/faq/data2/216985_.faqhttps://hoc247.net/image/faq/data2/216985_.data2https://hoc247.net/image/faq/data2/216985_.563596_.12

    g. (x.44https:https://hoc247.net/image/faq/data2/216985_.https://hoc247.net/image/faq/data2/216985_.hoc247.nethttps://hoc247.net/image/faq/data2/216985_.imagehttps://hoc247.net/image/faq/data2/216985_.faqhttps://hoc247.net/image/faq/data2/216985_.data2https://hoc247.net/image/faq/data2/216985_.563596_.7+3https:https://hoc247.net/image/faq/data2/216985_.https://hoc247.net/image/faq/data2/216985_.hoc247.nethttps://hoc247.net/image/faq/data2/216985_.imagehttps://hoc247.net/image/faq/data2/216985_.faqhttps://hoc247.net/image/faq/data2/216985_.data2https://hoc247.net/image/faq/data2/216985_.563596_.7)11https:https://hoc247.net/image/faq/data2/216985_.https://hoc247.net/image/faq/data2/216985_.hoc247.nethttps://hoc247.net/image/faq/data2/216985_.imagehttps://hoc247.net/image/faq/data2/216985_.faqhttps://hoc247.net/image/faq/data2/216985_.data2https://hoc247.net/image/faq/data2/216985_.563596_.5-3https:https://hoc247.net/image/faq/data2/216985_.https://hoc247.net/image/faq/data2/216985_.hoc247.nethttps://hoc247.net/image/faq/data2/216985_.imagehttps://hoc247.net/image/faq/data2/216985_.faqhttps://hoc247.net/image/faq/data2/216985_.data2https://hoc247.net/image/faq/data2/216985_.563596_.7=-2

    h. x.13https:https://hoc247.net/image/faq/data2/216985_.https://hoc247.net/image/faq/data2/216985_.hoc247.nethttps://hoc247.net/image/faq/data2/216985_.imagehttps://hoc247.net/image/faq/data2/216985_.faqhttps://hoc247.net/image/faq/data2/216985_.data2https://hoc247.net/image/faq/data2/216985_.563596_.4+(-7https:https://hoc247.net/image/faq/data2/216985_.https://hoc247.net/image/faq/data2/216985_.hoc247.nethttps://hoc247.net/image/faq/data2/216985_.imagehttps://hoc247.net/image/faq/data2/216985_.faqhttps://hoc247.net/image/faq/data2/216985_.data2https://hoc247.net/image/faq/data2/216985_.563596_.6)x-5https:https://hoc247.net/image/faq/data2/216985_.https://hoc247.net/image/faq/data2/216985_.hoc247.nethttps://hoc247.net/image/faq/data2/216985_.imagehttps://hoc247.net/image/faq/data2/216985_.faqhttps://hoc247.net/image/faq/data2/216985_.data2https://hoc247.net/image/faq/data2/216985_.563596_.3=5https:https://hoc247.net/image/faq/data2/216985_.https://hoc247.net/image/faq/data2/216985_.hoc247.nethttps://hoc247.net/image/faq/data2/216985_.imagehttps://hoc247.net/image/faq/data2/216985_.faqhttps://hoc247.net/image/faq/data2/216985_.data2https://hoc247.net/image/faq/data2/216985_.563596_.12

    i.93https:https://hoc247.net/image/faq/data2/216985_.https://hoc247.net/image/faq/data2/216985_.hoc247.nethttps://hoc247.net/image/faq/data2/216985_.imagehttps://hoc247.net/image/faq/data2/216985_.faqhttps://hoc247.net/image/faq/data2/216985_.data2https://hoc247.net/image/faq/data2/216985_.563596_.17:x+(-4https:https://hoc247.net/image/faq/data2/216985_.https://hoc247.net/image/faq/data2/216985_.hoc247.nethttps://hoc247.net/image/faq/data2/216985_.imagehttps://hoc247.net/image/faq/data2/216985_.faqhttps://hoc247.net/image/faq/data2/216985_.data2https://hoc247.net/image/faq/data2/216985_.563596_.17):x+22https:https://hoc247.net/image/faq/data2/216985_.https://hoc247.net/image/faq/data2/216985_.hoc247.nethttps://hoc247.net/image/faq/data2/216985_.imagehttps://hoc247.net/image/faq/data2/216985_.faqhttps://hoc247.net/image/faq/data2/216985_.data2https://hoc247.net/image/faq/data2/216985_.563596_.7:52https:https://hoc247.net/image/faq/data2/216985_.https://hoc247.net/image/faq/data2/216985_.hoc247.nethttps://hoc247.net/image/faq/data2/216985_.imagehttps://hoc247.net/image/faq/data2/216985_.faqhttps://hoc247.net/image/faq/data2/216985_.data2https://hoc247.net/image/faq/data2/216985_.563596_.3=4https:https://hoc247.net/image/faq/data2/216985_.https://hoc247.net/image/faq/data2/216985_.hoc247.nethttps://hoc247.net/image/faq/data2/216985_.imagehttps://hoc247.net/image/faq/data2/216985_.faqhttps://hoc247.net/image/faq/data2/216985_.data2https://hoc247.net/image/faq/data2/216985_.563596_.11

    j. 17https:https://hoc247.net/image/faq/data2/216985_.https://hoc247.net/image/faq/data2/216985_.hoc247.nethttps://hoc247.net/image/faq/data2/216985_.imagehttps://hoc247.net/image/faq/data2/216985_.faqhttps://hoc247.net/image/faq/data2/216985_.data2https://hoc247.net/image/faq/data2/216985_.563596_.2-|2x-3https:https://hoc247.net/image/faq/data2/216985_.https://hoc247.net/image/faq/data2/216985_.hoc247.nethttps://hoc247.net/image/faq/data2/216985_.imagehttps://hoc247.net/image/faq/data2/216985_.faqhttps://hoc247.net/image/faq/data2/216985_.data2https://hoc247.net/image/faq/data2/216985_.563596_.4|=-7https:https://hoc247.net/image/faq/data2/216985_.https://hoc247.net/image/faq/data2/216985_.hoc247.nethttps://hoc247.net/image/faq/data2/216985_.imagehttps://hoc247.net/image/faq/data2/216985_.faqhttps://hoc247.net/image/faq/data2/216985_.data2https://hoc247.net/image/faq/data2/216985_.563596_.4

    k. (x+1https:https://hoc247.net/image/faq/data2/216985_.https://hoc247.net/image/faq/data2/216985_.hoc247.nethttps://hoc247.net/image/faq/data2/216985_.imagehttps://hoc247.net/image/faq/data2/216985_.faqhttps://hoc247.net/image/faq/data2/216985_.data2https://hoc247.net/image/faq/data2/216985_.563596_.5)^2+17https:https://hoc247.net/image/faq/data2/216985_.https://hoc247.net/image/faq/data2/216985_.hoc247.nethttps://hoc247.net/image/faq/data2/216985_.imagehttps://hoc247.net/image/faq/data2/216985_.faqhttps://hoc247.net/image/faq/data2/216985_.data2https://hoc247.net/image/faq/data2/216985_.563596_.25=26https:https://hoc247.net/image/faq/data2/216985_.https://hoc247.net/image/faq/data2/216985_.hoc247.nethttps://hoc247.net/image/faq/data2/216985_.imagehttps://hoc247.net/image/faq/data2/216985_.faqhttps://hoc247.net/image/faq/data2/216985_.data2https://hoc247.net/image/faq/data2/216985_.563596_.25

    l. -32https:https://hoc247.net/image/faq/data2/216985_.https://hoc247.net/image/faq/data2/216985_.hoc247.nethttps://hoc247.net/image/faq/data2/216985_.imagehttps://hoc247.net/image/faq/data2/216985_.faqhttps://hoc247.net/image/faq/data2/216985_.data2https://hoc247.net/image/faq/data2/216985_.563596_.27-(3x-7https:https://hoc247.net/image/faq/data2/216985_.https://hoc247.net/image/faq/data2/216985_.hoc247.nethttps://hoc247.net/image/faq/data2/216985_.imagehttps://hoc247.net/image/faq/data2/216985_.faqhttps://hoc247.net/image/faq/data2/216985_.data2https://hoc247.net/image/faq/data2/216985_.563596_.9)^3=-24https:https://hoc247.net/image/faq/data2/216985_.https://hoc247.net/image/faq/data2/216985_.hoc247.nethttps://hoc247.net/image/faq/data2/216985_.imagehttps://hoc247.net/image/faq/data2/216985_.faqhttps://hoc247.net/image/faq/data2/216985_.data2https://hoc247.net/image/faq/data2/216985_.563596_.27

    Theo dõi (0) 1 Trả lời
  • Đào Lê Hương Quỳnh

    tính

    B = \(\dfrac{1}{18}+\dfrac{1}{54}+\dfrac{1}{108}+...+\dfrac{1}{990}\)

    Theo dõi (0) 1 Trả lời
  • thu thủy

    tìm x biết:................

    xhttps:https://hoc247.net/image/faq/data2/216985_.https://hoc247.net/image/faq/data2/216985_.hoc247.nethttps://hoc247.net/image/faq/data2/216985_.imagehttps://hoc247.net/image/faq/data2/216985_.faqhttps://hoc247.net/image/faq/data2/216985_.data2https://hoc247.net/image/faq/data2/216985_.563596_.3-1https:https://hoc247.net/image/faq/data2/216985_.https://hoc247.net/image/faq/data2/216985_.hoc247.nethttps://hoc247.net/image/faq/data2/216985_.imagehttps://hoc247.net/image/faq/data2/216985_.faqhttps://hoc247.net/image/faq/data2/216985_.data2https://hoc247.net/image/faq/data2/216985_.563596_.2=1https:https://hoc247.net/image/faq/data2/216985_.https://hoc247.net/image/faq/data2/216985_.hoc247.nethttps://hoc247.net/image/faq/data2/216985_.imagehttps://hoc247.net/image/faq/data2/216985_.faqhttps://hoc247.net/image/faq/data2/216985_.data2https://hoc247.net/image/faq/data2/216985_.563596_.5

    Theo dõi (0) 1 Trả lời