Bài tập 17 trang 130 SGK Hình học 12 NC

A. \(I\left( {2; - 1; - 1} \right);R = 9\)

B. \(I\left( { - 2;1;1} \right);R = 9\)

C. \(I\left( { - 2;1;1} \right);R = 3\)

D. \(I\left( {2; - 1; - 1} \right);R = 3\)

A. \(l = \sqrt {53} \)

B. \(l = \sqrt {37} \)

C. \(l = \sqrt {117} \)

D. \(l = \sqrt {101} \)

A. \(P =  - 14\)                B. \(P = 22\)

C. \(P = 18\)                   D. \(P =  - 10\)

A. \(OM = \sqrt {35} \)   

B. \(OM = 2\sqrt {35} \)

C. \(OM = \frac{{\sqrt {14} }}{2}\)                  

D. \(OM = \sqrt 5 \)

A. \(V = \frac{\pi }{6}\left( {3{\pi ^2} + 4\pi  - 8} \right)\)

B. \(V = \frac{\pi }{{16}}\left( {3{\pi ^2} - 4\pi  - 8} \right)\)

C. \(V = \frac{\pi }{8}\left( {3{\pi ^2} + 4\pi  - 8} \right)\)

D. \(V = \frac{1}{{16}}\left( {3{\pi ^2} - 4\pi  - 8} \right)\)

A. \(S = 2\sqrt {61} \)     

B. \(S = \frac{{\sqrt {61} }}{2}\)

C. \(S = \frac{{\sqrt {61} }}{3}\)                      

D. \(S = \sqrt {61} \)

A. \(\frac{{x + 2}}{{ - 1}} = \frac{{y + 1}}{2} = \frac{{z - 1}}{{ - 1}}\)

B. \(\frac{x}{1} = \frac{{y - 5}}{{ - 2}} = \frac{{z + 3}}{1}\)

C. \(\frac{{x - 2}}{1} = \frac{{y - 1}}{{ - 1}} = \frac{{z + 1}}{2}\)

D. \(\frac{{x + 1}}{2} = \frac{{y - 2}}{1} = \frac{{z + 1}}{{ - 1}}\)

A. \(\frac{x}{1} = \frac{{y - 2}}{2} = \frac{{z - 3}}{1}\)

B. \(\frac{{x + 1}}{2} = \frac{y}{4} = \frac{{z + 2}}{{ - 2}}\)

C. \(\frac{{x + 1}}{{ - 2}} = \frac{y}{{ - 4}} = \frac{{z + 2}}{{ - 2}}\)

D. \(\frac{{x - 1}}{2} = \frac{{y - 4}}{2} = \frac{{z - 4}}{2}\)

A. \(P = 5.\)                    B. \(P =  - 1\)

C. \(P = 6\)                     D. \(P = 3\)

A. \(k = \frac{{66}}{{49}}\)                              B. \(k = \frac{{36}}{{29}}\)

C. \(k = \frac{{74}}{{49}}\)                              D. \(k = \frac{{12}}{7}\)

A. \( - y + z - 4 = 0\)

B. \(y - z - 1 = 0\)

C. \(y + z - 4 = 0\)

D. \(3x - 3z - 4 = 0\)

A. \(k =  - 5.\)                 B. \(k = \frac{1}{5}\)

C. \(k = 5.\)                    D. \(k =  - \frac{1}{5}\)