Bài tập 1 trang 13 VBT Toán 5 tập 1

a)  \(5\dfrac{1}{{7}} = \dfrac{{36}}{{7}}\;;\;\;2\dfrac{6}{{7}} = \dfrac{{20}}{{7}}.\)

Mà \(\dfrac{{36}}{{7}} > {\rm{ }}\dfrac{{20}}{{7}}\)

Vậy: \(5\dfrac{1}{{7}} > {\rm{ }}2\dfrac{6}{{7}}\)

b) \(3\dfrac{2}{{7}} = \dfrac{{23}}{{7}}\;;\;\;3\dfrac{5}{{7}} = \dfrac{{26}}{{7}}\)

Mà \(\dfrac{{23}}{{7}} < \dfrac{{26}}{{7}}\)

Vậy : \(3\dfrac{2}{{7}} < {\rm{ }}3\dfrac{5}{{7}}\)

c) \(8\dfrac{6}{{10}} = \dfrac{{86}}{{10}}\;;\;\;8\dfrac{3}{{5}} = \dfrac{{43}}{{5}}\)

Mà \(\dfrac{{43}}{{5}} = \dfrac{{43 \times 2}}{{5 \times}} =\dfrac{{86}}{{10}}\)

Vậy: \(8\dfrac{6}{{10}} = {\rm{ }}6\dfrac{3}{{5}}\)

d) \(9\dfrac{1}{{2}} = \dfrac{{19}}{{2}} \;;\;\;5\dfrac{1}{2} = \dfrac{{11}}{2}\)

Mà \(\dfrac{{19}}{2} > \dfrac{{11}}{2}\)

Vậy : \(9\dfrac{1}{{2}} > {\rm{ }}5\dfrac{1}{2}\)

-- Mod Toán lớp 5 HỌC247