Hỏi đáp về Ôn tập cuối năm - Hình học 12

A. \(\left( { - 9;12;0} \right)\)

B. \(\left( {9; - 12;0} \right)\)

C. \(\left( {0;9; - 12} \right)\)

D. \(\left( {0; - 9;12} \right)\)

A. \({\left( {x - 1} \right)^2} + {\left( {y - 2} \right)^2} + {z^2} = 16.\)

B. \({\left( {x - 1} \right)^2} + {\left( {y - 2} \right)^2} + {z^2} = 7.\)

C. \({\left( {x - 1} \right)^2} + {\left( {y - 2} \right)^2} + {z^2} = 25.\)

D. \({\left( {x - 1} \right)^2} + {\left( {y - 2} \right)^2} + {z^2} = 9.\)

A. \(I\left( { - 4;1;0} \right);\,\,R = 4.\)

B. \(I\left( {8; - 2;0} \right);\,\,R = 2\sqrt 7 .\)

C. \(I\left( {4; - 1;0} \right);\,\,R = 4.\)

D. \(I\left( {4; - 1;0} \right);\,\,R = 16.\)

A. \(1\)                            B. \(\frac{{11}}{3}\)

C. \(3\)                            D. \(\frac{1}{3}\)

A. \(\frac{{2\pi }}{3}.\)         B. \(\frac{{4\pi }}{3}.\)

C. \(\frac{{8\pi }}{{15}}.\)     D. \(\frac{{16\pi }}{{15}}.\)

A. \(\left\{ \begin{array}{l}x = 2 + 2t\\y =  - 3t\\z =  - 1 + t\end{array} \right.\)

B. \(\left\{ \begin{array}{l}x = 4 + 2t\\y =  - 6\\z = 2 - t\end{array} \right.\)

C. \(\left\{ \begin{array}{l}x =  - 2 + 2t\\y =  - 3t\\z = 2 - t\end{array} \right.\)

D. \(\left\{ \begin{array}{l}x =  - 2 + 4t\\y =  - 6t\\z = 1 + 2t\end{array} \right.\)

A. \(\left( {2;2;6} \right)\)

B. \(\left( {0; - 4; - 4} \right)\)

C. \(\left( {0; - 2; - 2} \right)\)

D. \(\left( {1;1;3} \right)\)

A. \(\overrightarrow n  = \left( {2; - 1;1} \right)\).

B. \(\overrightarrow n  = \left( {2;0; - 1} \right)\)

C. \(\overrightarrow n  = \left( {2;0;1} \right)\)

D. \(\overrightarrow n  = \left( {2;1; - 1} \right)\)

A. \({\left( {x + 1} \right)^2} + {\left( {y - 1} \right)^2} + {\left( {z + 2} \right)^2} = 25.\)

B. \({\left( {x + 1} \right)^2} + {\left( {y - 1} \right)^2} + {\left( {z + 2} \right)^2} = 5.\)

C. \({\left( {x - 2} \right)^2} + {\left( {y - 1} \right)^2} + {\left( {z - 2} \right)^2} = 25.\)

D. \({\left( {x - 1} \right)^2} + {\left( {y + 1} \right)^2} + {\left( {z - 2} \right)^2} = 25.\)

A. \(\sqrt {41} \)             B. 7.

C. 49.                             D. \(\sqrt 7 \)

A. \(S = \frac{{1075}}{{192}}\)  

B. \(S = \frac{{135}}{{64}}\)

C. \(S = \frac{{185}}{{24}}\)

D. \(S = \frac{{335}}{{96}}\)

A. \({\left( {x + \frac{3}{2}} \right)^2} + {y^2} + {\left( {z + 2} \right)^2} = \frac{9}{4}\) 

B. \({\left( {x + \frac{3}{2}} \right)^2} + {y^2} + {\left( {z + 2} \right)^2} = \frac{3}{2}\)

 C. \({\left( {x - \frac{3}{2}} \right)^2} + {y^2} + {\left( {z - 2} \right)^2} = \frac{3}{2}\)

D. \({\left( {x - \frac{3}{2}} \right)^2} + {y^2} + {\left( {z - 2} \right)^2} = \frac{9}{4}\)

A. \(\left( {2;4; - 2} \right)\)

B. \(\left( { - 2;2;4} \right)\)

C. \(\left( { - 1;1;2} \right)\)

D. \(\left( { - 2; - 4;2} \right)\)

A. \(M\left( {0;0; - 3} \right)\)  

B. \(M\left( {0;0;3} \right)\)

C. \(M\left( {0;0; - 4} \right)\)

D. \(M\left( {0;0;4} \right)\)

A. \(0\)                                   B. \(2\)

C. \(1\)                                  D. \(3\)

A. \(\left( {3;6;8} \right)\)  

B. \(\left( {1; - 4; - 5} \right)\)

C. \(\left( { - 1;2;3} \right)\)

D. \(\left( {0;6;8} \right)\)

A. \(m = 1\)

B. Không tồn tại m

C. \(m =  - 2\)

D. \(m = 2\)

A. \({\left( {x - 2} \right)^2} + {\left( {y - 1} \right)^2} + {\left( {z - 1} \right)^2} = 9\)  

B. \({\left( {x - 2} \right)^2} + {\left( {y - 1} \right)^2} + {\left( {z - 1} \right)^2} = 2\)

C. \({\left( {x - 2} \right)^2} + {\left( {y - 1} \right)^2} + {\left( {z - 1} \right)^2} = 4\)

D. \({\left( {x - 2} \right)^2} + {\left( {y - 1} \right)^2} + {\left( {z - 1} \right)^2} = 36\)

A. \(M\left( { - 1;0;4} \right)\)

B. \(M\left( {0;0;5} \right)\)

C. \(M\left( { - 5; - 2;2} \right)\)

D. \(M\left( { - 3; - 1;3} \right)\)

A. \(S = \frac{{13}}{6}\)

B. \(S = \frac{7}{6}\)

C. \(S = \frac{1}{6}\)

D. \(S = \frac{{17}}{6}\)

A. \(x = 0\)

B. \(y + z = 0\)

C. \(x = y + z\)

D. \(y - z = 0\)

A. \(A\left( {3;0; - 1} \right)\)  

B. \(A\left( { - 1;0;3} \right)\)

C. \(A\left( { - 1;3;0} \right)\)

D. \(A\left( {3; - 1;0} \right)\)

A. \(z =  - 1 + 3i\)  

B. \(z =  - 3 + i\)

C. \(z = 1 - 3i\)

D. \(z = 3 - i\)

A. \(\overrightarrow {{n_1}}  = \left( {6;3;2} \right)\)

B. \(\overrightarrow {{n_2}}  = \left( {6;2;3} \right)\)

C. \(\overrightarrow {{n_3}}  = \left( {3;6;2} \right)\)

D. \(\overrightarrow {{n_4}}  = \left( {2;3;6} \right)\)