Cho dãy chuyển hóa sau: CaC2=> Z => Y => Z

\(CaC_{2} \xrightarrow[]{ \ H_{2}O \ }X\xrightarrow[(Pb.PdCO_{3})]{ + H_{2}} Y \xrightarrow[H_{2}SO_{4}, \ t^0]{+H_{2}} Z\)
\(\\ CaC_{2}+2H_{2}O \xrightarrow[]{ \ \ \ \ }Ca(OH)_{2} + C_{2}H_{2} \ (X) \\ CH\equiv CH+H_{2}\xrightarrow[]{ \ Pb.PdCO_{3} \ } CH_{2}=CH_{2} \ (Y) \\ \begin{matrix} CH_{2}=CH_{2}+H_{2}O\xrightarrow[ t^0]{ \ H_{2}SO_{4} \ } \\ \ \end{matrix} \begin{matrix} CH_{3} - CH_{2} \\ \ \ \ \ \ \ \ \ \ \ ^| \\ \ \ \ \ \ \ \ \ \ \ OH \end{matrix} \begin{matrix} \ (Z) \\ \ \end{matrix}\)
⇒ Chọn A