Hỏi đáp về Hàm số lượng giác

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            [faq_title] => Giải phương trình (y = 4sqrt {{mathop{
m s}
olimits} {
m{in2x + 3}}}  - 1).
            [faq_code] => 
            [faq_content] => Ai giúp mk giải ý này với ạ. Em c.ơn mn nhiều ạ 

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            [faq_createdate] => 2020-09-14 21:23:03
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            [faq_title] => Tìm nghiệm của phương trình sin3x=cosx
            [faq_code] => 
            [faq_content] => Giúp với ạ
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            [faq_title] => Tìm tập xác định của hàm số y=sinx. cosx
            [faq_code] => 
            [faq_content] => Tìm tập xác định của hàm số y=sinx  cosx
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            [faq_createdate] => 2020-09-13 20:19:46
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            [faq_content] => Tìm tập xác định của hàm số y=sinx cosx
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            [faq_title] => Xác định tính chẵn lẻ của hàm số y = cos2x/x
            [faq_code] => 
            [faq_content] => 

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            [faq_title] => Tìm tập xác định hàm số: (y = frac{{	an {
m{x}}}}{{sin x.cos {
m{x}}}})
            [faq_code] => 
            [faq_content] => 

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            [faq_title] => Giải phương trình (sin (x + frac{pi }{3}) + cos (x + frac{pi }{3}) = sqrt {2sin (x + frac{pi }{6})} )
            [faq_code] => 
            [faq_content] => 
sin(x+pi/3)+cos(x+pi/3)= căn 2sin(x+pi/6)
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            [faq_code] => 
            [faq_content] => 

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            [faq_code] => 
            [faq_content] => a, y= sinx^3 . cos^3x   tanxb, y= |x|   cos^4x c, y= x^3 . sin2x
            [subject_code] => toan-hoc
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            [faq_title] => Tìm TXĐ của hàm số sau y= (cos x căn 3)/(2sin(x-pi/4) căn 2
            [faq_code] => 
            [faq_content] => Tìm TXĐ của hàm số sau
y= (cos x   căn 3)/(2sin(x-pi/4)  căn 2
            [subject_code] => toan-hoc
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            [faq_title] => Tập xác định hàm số: (y = frac{{sin x + 1}}{{sin x - 2}})
            [faq_code] => 
            [faq_content] => Giúp mình với ạ 

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            [faq_code] => 
            [faq_content] => 
y = sinx - căn 3 cosx tính giá trị lớn nhất nhỏ nhất 
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            [faq_content] => Giúp mình giải câu tìm x biếta). 8sinx.cosx.cos2x.cos4x - 1 = 0b). Cos6x   2sin3x - 1 = 0
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ight| - left| {x + 1} 
ight|}}{{sin x}})
            [faq_code] => 
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            [subject_code] => toan-hoc
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            [faq_content] => 

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            [faq_content] => 

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            [faq_content] => Tìm tập xác định
1/ tanx
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            [faq_title] => Tìm điều kiện xác định của hàm số y = √cos x?
            [faq_code] => 
            [faq_content] => 
Điều kiện xác định của hàm số y = √cos x
            [subject_code] => toan-hoc
            [grade_code] => lop-11
            [faq_createdate] => 2020-07-29 17:31:42
            [faq_num_answer] => 5
            [faq_num_follow] => 0
            [faq_flag] => 0
            [faq_status] => 1
            [faq_reason] => 
            [member_id] => 757114
            [user_username] => 
            [member_email] => quynhquang692@gmail.com
            [member_firstname] => quang
            [member_lastname] => địch
            [member_avata] => images/avatar/library/757115.jpg
            [member_createdate] => 2020-07-29 17:29:41
            [member_numpoint] => 19
            [member_isninja] => 0
            [faq_point] => 2
        )

    [24] => Array
        (
            [faq_id] => 550556
            [faq_title] => Tìm m để hàm số \(y = \sqrt{2m} -3\cos x\) xác định trên R?
            [faq_code] => 
            [faq_content] => 
tim m de ham so y=can 2m-3cosx xac dinh tren r
            [subject_code] => toan-hoc
            [grade_code] => lop-11
            [faq_createdate] => 2020-07-24 15:11:53
            [faq_num_answer] => 3
            [faq_num_follow] => 0
            [faq_flag] => 0
            [faq_status] => 1
            [faq_reason] => 
            [member_id] => 754417
            [user_username] => 
            [member_email] => nguyenhuyen24bn@gmail.com
            [member_firstname] => huyen
            [member_lastname] => nguyen thi
            [member_avata] => images/avatar/library/754418.jpg
            [member_createdate] => 2020-07-24 15:06:36
            [member_numpoint] => 15
            [member_isninja] => 0
            [faq_point] => 4
        )

)