Tính S_35+S_60+S_100 với Sn=1-2+3-4+...+(-1)^(n-1).n

bởi Bin Nguyễn 25/04/2019

Tính S35+S60+S100 với Sn=1-2+3-4+...+(-1)n-1.n

Câu trả lời (1)

  • Sn=2−4+6−8+...+(−1)n−1.nSn=2−4+6−8+...+(−1)n−1.n

    Sn=2−4+6−8+...+(−1)n:(−1).nSn=2−4+6−8+...+(−1)n:(−1).n

    Sn=2−4+6−8+...+nSn=2−4+6−8+...+n

    ⇒S35+S50+S100⇒S35+S50+S100

    = (2−4+6−8+...+35)+(2−4+6−8+...+50)+(2−4+6−8+...+100)(2−4+6−8+...+35)+(2−4+6−8+...+50)+(2−4+6−8+...+100)

    = 17.(−2)+35+25.(−2)+50.(−2)

    Tick mình nha camr ơn nhiều!

    bởi nguyên trần liên trâm 25/04/2019
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