Câu hỏi trắc nghiệm (10 câu):
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Câu 1:
Tam giác ABC có \(AB = 3,AC = 6,{\rm{\;}}\widehat {BAC} = 60^\circ \). Tính diện tích tam giác ABC.
- A. \({S_{\Delta ABC}} = 9\sqrt 3 \).
- B. \({S_{\Delta ABC}} = \frac{{9\sqrt 3 }}{2}\).
- C. \({S_{\Delta ABC}} = 9\).
- D. \({S_{\Delta ABC}} = \frac{9}{2}\).
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- A. \({S_{\Delta ABC}} = 8\)
- B. \({S_{\Delta ABC}} = 4\sqrt 3 \)
- C. \({S_{\Delta ABC}} = 4\)
- D. \({S_{\Delta ABC}} = 8\sqrt 3 \)
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- A. \({S_{\Delta ABC}} = 16\)
- B. \({S_{\Delta ABC}} = 48\)
- C. \({S_{\Delta ABC}} = 24\)
- D. \({S_{\Delta ABC}} = 84\)
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- A. \(h = 3\sqrt 3 \)
- B. \(h = \sqrt 3 \)
- C. \(h\; = \;3\)
- D. \(h = \frac{3}{2}\)
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- A. \(h = 2\sqrt 3 \)
- B. \(h = 4\sqrt 3 \)
- C. \(h = 2\)
- D. \(h = 4\)
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- A. \(BB' = 8\)
- B. \(BB' = \frac{{84}}{5}\)
- C. \(BB' = \frac{{168}}{{17}}\)
- D. \(BB' = \frac{{84}}{{17}}\)
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- A. \(\sin \;A = \frac{{\sqrt 3 }}{2}\)
- B. \(\sin \;A = \frac{3}{8}\)
- C. \(\sin \;A = \frac{4}{5}\)
- D. \(\sin \;A = \frac{8}{9}\)
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- A. \(2{a^2}\)
- B. \({a^2}\sqrt 2 \)
- C. \({a^2}\)
- D. \({a^2}\sqrt 3 \)
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- A. \({\rm{50\;c}}{{\rm{m}}^{\rm{2}}}\)
- B. \({\rm{50}}\sqrt 2 {\rm{\;c}}{{\rm{m}}^{\rm{2}}}\)
- C. \({\rm{75\;c}}{{\rm{m}}^{\rm{2}}}\)
- D. \({\rm{15}}\sqrt {105} {\rm{\;c}}{{\rm{m}}^{\rm{2}}}\)
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- A. 2S;
- B. 3S;
- C. 4S;
- D. 6S;
