Trần Quang Trường's Profile

Câu 1:

program In_ra_lai;

uses crt;

var a,b,TG:real;

begin

write(''Nhap so a = '); read(a);

write('Nhap so b = '); read(b);

TG:=a;

a:=b;

b:=TG;

writeln('Sau khi doi gia tri thi a = ',a);

writeln('Sau khi doi gia tri thi b = ',b);

readln;

end.

a. Chiều dài là: 32 : 8 = 4(cm)

b. Chu vi là: (8 + 4) x 2 = 24 cm

1 + a x 1 + b = (1 x 1) + (a + b)

= a + b

Số là bội của 3 và ước của 54 là 3

Cho hơi nước qua than nóng đỏ,được hỗn hợp A gồm 3 khí là chất vô cơ X,Y,Z.Xác định X, Y,Z biết :
X +H2O tạo ra Y va Z
Z+ C tạo ra CO
a.Tính thành phần % về thể tích mỗi khí X,Y ,Z trong A biết MA=15.5g
b.Cách tách từng khí ra khỏi hỗn hợp.

Cho hơi nước qua than nóng đỏ,được hỗn hợp A gồm 3 khí là chất vô cơ X,Y,Z.Xác định X, Y,Z biết :
X +H2O tạo ra Y va Z
Z+ C tạo ra CO
a.Tính thành phần % về thể tích mỗi khí X,Y ,Z trong A biết MA=15.5g
b.Cách tách từng khí ra khỏi hỗn hợp.

1: Gets - goes

2: doesn't go

3: am living

4: do

5: tell

6: is .. doing ..?-  is playing

7: reads - listens

8: does.. do? - is

My secondary school is a place that bears all the hallmarks of my childhood memories. It is placed in the center of my district. Surrounded by a paddy-field, it enjoys lined- trees and colorful garden, which creates a wonderful view. Moreover, this school was designed with a large- scale plan. It is a 2 storied building of u shape with capacity of 1000 people and it was invested heavily in infrastructures with well- equipped classrooms. In a good environment, students are given many precious chances to discover and develop their inner talents. Besides modern facilities, this school is also well- known for enthusiastic and qualified teachers who are always dedicated and devoted themselves to teaching career. In conclusion, studied in this school for four years, it has become an indispensable part in my life.

10000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000...0 + 100000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000...0 = 2000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000...0