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Tính (1/4-1/4+1/9/1/9):(2/3+7/15/2/5-1/6)

bài 1 : tính

1) 5/8 . 7/3 - 5/2 . 1/8 2) 21/10 . 3/4 - 21/10 - 3/4 3) -4 / 11 : -6/11 4) 2/7 . 14/3 -1 5) 4/7 : ( 1/5 . 4/7 ) 6) 12/7 . 7/4 + 35/11 : 245/121

7) ( 4/3 + 8/3 ) . ( 7/4 - 6/4 ) : ( 6/5 + 12/5 + 1/5 ) 8) ( 1/4 - 1/4 + 1/9 / 1/9 ) : ( 2/3 + 7/15 / 2/5 - 1/6 )

9) ( ( 2/193 - 3/389 ) . 193/17 + 33/34 ) : (( 7/1931 - 11 / 3862 ) . 1931 / 25 + 9/2 )

chú ý :

/ là phần nha , nếu có 2 cái (( là sẽ có ngoặc vuông nha ! nhanh nha mình đang gấp lắm

Theo dõi Vi phạm
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Trả lời (1)

  • Bài 1: Tính

    \(\text{1)}\) \(\dfrac{5}{8}.\dfrac{7}{30}-\dfrac{5}{2}.\dfrac{1}{8}\)

    \(=\dfrac{5}{8}.\dfrac{7}{30}-\dfrac{5}{8}.\dfrac{1}{2}\)

    \(=\dfrac{5}{8}.\left(\dfrac{7}{30}-\dfrac{1}{2}\right)\)

    \(=\dfrac{5}{8}.\dfrac{-4}{15}\)

    \(=\dfrac{-1}{6}\)

    \(\text{2)}\) \(\dfrac{21}{10}.\dfrac{3}{4}-\dfrac{21}{10}-\dfrac{3}{4}\)

    \(=\dfrac{63}{40}-\dfrac{21}{10}-\dfrac{3}{4}\)

    \(=\dfrac{-21}{40}-\dfrac{3}{4}\)

    \(=\dfrac{-51}{40}\)

    \(\text{3)}\) \(\dfrac{-4}{11}:\dfrac{-6}{11}\)

    \(=\dfrac{-4}{11}.\dfrac{11}{-6}\)

    \(=\dfrac{4}{6}\)

    \(\text{4)}\) \(\dfrac{2}{7}.\dfrac{14}{3}-1\)

    \(=\dfrac{4}{3}-1\)

    \(=\dfrac{1}{3}\)

    \(\text{5)}\) \(\dfrac{4}{7}:\left(\dfrac{1}{5}.\dfrac{4}{7}\right)\)

    \(=\dfrac{4}{7}:\dfrac{1}{5}:\dfrac{4}{7}\)

    \(=1:\dfrac{1}{5}\)

    \(=5\)

    \(\text{6)}\) \(\dfrac{12}{7}.\dfrac{7}{4}+\dfrac{35}{11}:\dfrac{245}{121}\)

    \(=3+\dfrac{35}{11}.\dfrac{121}{245}\)

    \(=3+\dfrac{11}{7}\)

    \(=3\dfrac{11}{7}=\dfrac{32}{7}\)

    \(\text{7)}\) \(\left(\dfrac{4}{3}+\dfrac{8}{3}\right).\left(\dfrac{7}{4}-\dfrac{6}{4}\right):\left(\dfrac{6}{5}+\dfrac{12}{5}+\dfrac{1}{5}\right)\)

    \(=4.\left(\dfrac{7}{4}-\dfrac{6}{4}\right):\left(\dfrac{6}{5}+\dfrac{12}{5}+\dfrac{1}{5}\right)\)

    \(=4.\dfrac{1}{4}:\left(\dfrac{6}{5}+\dfrac{12}{5}+\dfrac{1}{5}\right)\)

    \(=4.\dfrac{1}{4}:\dfrac{19}{5}\)

    \(=1:\dfrac{19}{5}\)

    \(=\dfrac{5}{19}\)

    \(\text{8)}\) \(\left(\dfrac{1}{4}-\dfrac{1}{4}+\dfrac{\dfrac{1}{9}}{\dfrac{1}{9}}\right):\left(\dfrac{2}{3}+\dfrac{\dfrac{7}{15}}{\dfrac{2}{5}}-\dfrac{1}{6}\right)\)

    \(=\left(0+1\right):\left(\dfrac{2}{3}+\dfrac{7}{15}:\dfrac{2}{5}-\dfrac{1}{6}\right)\)

    \(=1:\left(\dfrac{2}{3}+\dfrac{7}{6}-\dfrac{1}{6}\right)\)

    \(=1:\left(\dfrac{2}{3}+1\right)\)

    \(=1:\dfrac{5}{3}\)

    \(=\dfrac{3}{5}\)
    \(\text{9)}\)

    \(\left[\left(\dfrac{2}{193}-\dfrac{3}{389}\right).\dfrac{193}{17}+\dfrac{33}{34}\right]:\left[\left(\dfrac{7}{1931}-\dfrac{11}{3862}\right).\dfrac{1931}{25}+\dfrac{9}{2}\right]\)

    \(=\left[\dfrac{199}{75077}.\dfrac{193}{17}+\dfrac{33}{34}\right]:\left[\left(\dfrac{7}{1931}-\dfrac{11}{3862}\right).\dfrac{1931}{25}+\dfrac{9}{2}\right]\)

    \(=\left[\dfrac{199}{6613}+\dfrac{33}{34}\right]:\left[\left(\dfrac{7}{1931}-\dfrac{11}{3862}\right).\dfrac{1931}{25}+\dfrac{9}{2}\right]\)

    \(=\dfrac{13235}{13226}:\left[\left(\dfrac{7}{1931}-\dfrac{11}{3862}\right).\dfrac{1931}{25}+\dfrac{9}{2}\right]\)

    \(=\dfrac{13235}{13226}:\left[\dfrac{3}{3862}.\dfrac{1931}{25}+\dfrac{9}{2}\right]\)

    \(=\dfrac{13235}{13226}:\left[\dfrac{3}{50}+\dfrac{9}{2}\right]\)

    \(=\dfrac{13235}{13226}:\dfrac{114}{25}\)

    \(=\dfrac{330875}{1507764}\)

      bởi Nguyentuong Vy 11/01/2019
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