Một sóng hình sin lan truyền trên một sợi dây đàn hồi theo chiều từ M - O

Từ đồ thị, ta có:

\(\lambda =64\)cm → \(T=\frac{\lambda }{v}=\frac{\left( 64 \right)}{\left( 64 \right)}=1\)s.

\(\left\{ \begin{align} & {{\left( {{u}_{N}} \right)}_{{{t}_{1}}}}=a\cos \left( \frac{2\pi d}{\lambda } \right)=a\cos \left( \frac{2\pi .1}{8} \right)=\frac{\sqrt{2}}{2}a \\ & {{\left( {{v}_{N}} \right)}_{{{t}_{1}}}}<0 \\ \end{align} \right.\)

\(\left\{ \begin{align} & {{\left( {{u}_{M}} \right)}_{{{t}_{1}}}}=\frac{\sqrt{2}}{2}a \\ & {{\left( {{v}_{M}} \right)}_{{{t}_{1}}}}>0 \\ \end{align} \right.\). \(\Delta \varphi =\omega \Delta t=\left( 2\pi \right)\left( \frac{1}{3} \right)=\frac{2\pi }{3}\) → \(\left\{ \begin{align} & {{v}_{N}}=-\omega a\cos \left( \frac{2\pi }{3}-\frac{\pi }{4} \right) \\ & {{v}_{M}}=-\omega a\sin \left( \frac{2\pi }{3}-\frac{\pi }{4} \right) \\ \end{align} \right.\)

→ \({{v}_{M}}-{{v}_{N}}=-\omega a\left( \sin \left( \frac{5\pi }{12} \right)-\sin \left( \frac{5\pi }{12} \right) \right)=-\left( 2\pi  \right).\left( 2 \right)\left( \sin \left( \frac{5\pi }{12} \right)-\sin \left( \frac{5\pi }{12} \right) \right)\approx 8,89\)cm/s.