Cho hai số phức z_1,z_2 thỏa mãn z_1,z_2 khác 0 z_1+z_2 khác 0 và 1/(z_1+z_2)=1/z_1+2/z_2. Tính môđun z_1/z_2

Ta có: \(\frac{1}{{{z_1} + {z_2}}} = \frac{1}{{{z_1}}} + \frac{2}{{{z_2}}} \Leftrightarrow \frac{{{z_1}}}{{{z_1} + {z_2}}} = 1 + \frac{{2{z_1}}}{{{z_2}}} \Leftrightarrow \frac{{\frac{{{z_1}}}{{{z_2}}}}}{{\frac{{{z_1}}}{{{z_2}}} + 1}} = 1 + \frac{{2{z_1}}}{{{z_2}}}\).

Đặt \(t = \frac{{{z_1}}}{{{z_2}}}\)

Khi đó \(\frac{t}{{t + 1}} = 1 + 2t \Rightarrow 2{t^2} + 2t + 1 = 0 \Rightarrow \left[ {\begin{array}{*{20}{c}} {t = \frac{{ - 1 + i}}{2}}\\ {t = \frac{{ - 1 - i}}{2}} \end{array}} \right. \Rightarrow \left| t \right| = \frac{{\sqrt 2 }}{2}.\)