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n_Fe=m/M=11,2/64=0,175(mol)
                  Fe + 2HCl --> FeCl₂ + H₂
Phản ứng     1   :    2    :      1     :  2
Đề bài     0,175 ->0,35 -> 0,175 ->0,35
V_H2=n.22,4=0,35.22,4=7,84(l)
m_HCl=n.M=0,35.36,5=12,775(g)

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a) viết phương trình phản ứngb)tính thể tích khí hidro(đktc)thi đượcc) tính khối lượng Axit Clohydric cần dùng

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