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Tìm x, biết (x+3)/2=(x+2)/3

Tìm x :

a) -(-7) - ( x + 4 ) = 6 - 2x

b) \(\frac{x+3}{2}=\frac{x+2}{3}\)

Theo dõi Vi phạm
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  • b) quy đồng bình thường

    MSC:=6

    \(\Leftrightarrow\frac{\left(x+3\right).3}{2.3}=\frac{\left(x+2\right).2}{3.2}\)

    Mẫu = nhau=> tử bằng nhau: \(\left(x+3\right).3=\left(x+2\right).2\Leftrightarrow3x+9=2x+4\)(1)

    Chuyển hết số hạng chứa "x" ẩn sang bên VT; hằng số để bên VP

    \(\left(1\right)\Leftrightarrow3x-2x=4-9\)

    \(\Leftrightarrow x=-5\) (hết!)

      bởi Hoàngg Lann 26/12/2018
    Like (0) Báo cáo sai phạm

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