Hòa tan hết 8,96 gam hỗn hợp X gồm Mg, MgCO3, Zn, ZnCO3 trong dung dịch chứa 0,43 mol KHSO4 và 0,05 mol HNO3.

\(\begin{array}{l} 8,96\,g\left\{ \begin{array}{l} Mg\\ Zn\\ C{O_3}\,(a\,mol) \end{array} \right. + \left\{ \begin{array}{l} 0,43\,mol\,KHS{O_4}\\ 0,05\,mol\,HN{O_3} \end{array} \right. \to \left\{ \begin{array}{l} {H_2}\,\,\,0,05\,mol\,\\ NO(0,1 - a)\,mol\\ C{O_2}\,\,a\,mol \end{array} \right. + Y\left\{ \begin{array}{l} {K^ + }\\ M{g^{2 + }}\\ Z{n^{2 + }}\\ N{H_4}^ + \,\,(a - 0,05)\,\,mol\\ S{O_4}^{2 - } \end{array} \right. + \,{H_2}O\\ BTo\,xi:\,\,\,{n_{{H_2}O}} = a\, + 0,15\, - (0,1 - a)\, = 2a + 0,05\\ BT\,hidro:\,0,48\, = 0,1 + 4a - 0,2 + 2{n_{{H_2}O}} \to a = 0,06.\\ BTKL:\,{m_{muoi\,Y}} = \,(8,96 + 0,43.136 + 0,05.63) - (0,05.2 + 0,04.30 + 44.0,06\, + 0,17.18) = 63,59\,gam \end{array}\)