Cho 8,45g Zn tác dụng với 5,376 lít khí Chlorine (đktc). Hỏi chất nào sau phản ứng còn dư

\(\begin{array}{l} {{\rm{n}}_{{\rm{Zn}}}} = \frac{{8,45}}{{65}} = 0,13\;{\rm{mol;}}\,\,\,\\ {n_{C{l_2}}} = \frac{{5,376}}{{22,4}} = 0,24\;{\rm{mol}}\\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\rm{Zn + C}}{{\rm{l}}_{\rm{2}}} \to {\rm{ZnC}}{{\rm{l}}_{\rm{2}}}\\ Ban\,{\rm{đầu:}}\,\,\,\,\,\,\,\,\,\,\,{\rm{0,13}}\,\,\,{\rm{0,24}}\\ Phản\ ứng:\,\,\,\,\,\,\,\,0,13\,\,\,0,13\,\,\,\,\,\,\,\,\,\,\,0,13\\ Sau:\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,0\,\,\,\,\,\,\,0,11\,\,\,\,\,\,\,\,\,\,\,\,0,13 \end{array}\)

Vạy chlorine dư 0,11 mol.