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Tìm tập hợp các số nguyên n để n/(n+3) có giá trị là số nguyên

tập hợp các số nguyên n để \(\dfrac{n}{n+3}\)có giá trị là số nguyên là S = {...}

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  • \(\dfrac{n}{n+3}=\dfrac{n+3-3}{n+3}\)

    Để \(\dfrac{n}{n+3}\in Z\Rightarrow3⋮n+3\)

    \(\Rightarrow n+3\inƯ\left(3\right)=\left(-3;-1;1;3\right)\)

    n+3 -3 -1 1 3
    n -6 -4 -2 0

      bởi Phạm Hà Trang 19/12/2018
    Like (0) Báo cáo sai phạm

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